32m^2+64m+24=0

Solution for 32m^2+64m+24=0 equation:

32m^2+64m+24=0

a = 32; b = 64; c = +24;
Δ = b2-4ac
Δ = 642-4·32·24
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-32}{2*32}=\frac{-96}{64}
=-1+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+32}{2*32}=\frac{-32}{64}
=-1/2
$